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If ax ^(2) + 2kxy + by ^(2) + 2gx + 2fy ...

If `ax ^(2) + 2kxy + by ^(2) + 2gx + 2fy + c =0` then `(dy)/(dx) =`

A

`(ax + by)/(hx + by )`

B

`(-(ax + hy))/(hx + by )`

C

`((ax + hy + g )/(hx + by + f))`

D

`-((ax + ky + g)/(kx + by + f))`

Text Solution

Verified by Experts

The correct Answer is:
A
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