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The amount of iron (Fe) in g which can b...

The amount of iron (Fe) in g which can be produced from 600g of magnetite ore is [Atomic mass of Fe : 55.8]

A

450

B

379

C

434

D

210

Text Solution

Verified by Experts

The correct Answer is:
C
`Fe_(3) O_(4) + 2C rarr 3Fe + 2CO_(2)`
1 moles of `Fe_(3)O_(4)` produce 3 moles of Fe
so, 600g of magnitite have `= (600)/(232)` moles = 2.5 mol
so, 2.5 moles of `Fe_(3)O_(4)` produce 7.75 moles of Fe So, mass of 7.75 moles of Fe is
`= 7.75 xx 55.83 = 434g " of " Fe`
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