A cricket ball of mass 150 g is moving with a speed of `12ms^(-1)` and is hit by a bat so that the ball is turned back with velocity of `20ms^(-1)` if duration of contact between bat and ball is 0.01 s then:

Options

A. `120N`
B. `280N`
C. `380N`
D. `480N`

Answer

D

Explanation

According to given question, change in momentum of the ball
`Deltap=p_(f)-p_(i)=m(v-u)=15xx10^(-3)[20-(-12)]`
So, by impulse- momentum theorem, impulse `I=Deltap=4.8Ns`
And by time averaged definition of force in case of impulse
`F_(av)=(I)/(Deltat)=(Deltap)/(Deltat)=(4.80)/(0.01)=480N`