A bullet mass 10gm is fired from a gun of mass 1 kg . If the recoil velocity is 5 `m//s`, the velocity of the muzzle is

Explanation

From the law of conservation of momentum
`m_(G)v_(G)=m_(B)v_(B)`
where, `m_(G),v_(G)=`mass of gun and velocity of gun
`m_(B),v_(B)=` mass and velocity of bullet
`implies v_(B)=(m_(G)v_(G))/(m_(B))=(1xx5)/(10xx10^(-3))=500ms^(-1)`