If in a stationary lift, a man is standing with a bucket full of water, having a hole at its bottom. The rate of flow of water through this hole is `R_(0)`. If the lift starts to move up and down with same acceleration and then that rates of flow of water are `R_(u)` and , `R_(d)`, then

Explanation

Rate of flow will be more when elevator will move in upward direction with some acceleration because the net downward pull will be more and vice-versa.
`F_("upward")(R_(u))=`m(g+a)
`F_("downward")(R_(d))"=m(g+a)" implies F_("at rest")(R_(o))=mg`
Thus, relation between `R_(u).R_(o)" and " R_(d) " is " R_(u)gt R_(o)gt R_(d)`