A particle is shifted from point (0,0,1m)to (1m,1m,2m), under simultanoeus action of several forces. Two of the forces are `F_(1)=(2hati+3j-k)N " and " F_(2)=(hati-2hatj+2hatk)N`. Find work done by resultant of these two forces.

Explanation

To find the work done by the resultant of the two forces \( F_1 \) and \( F_2 \) on a particle that is displaced from point \( (0,0,1 \, \text{m}) \) to \( (1 \, \text{m}, 1 \, \text{m}, 2 \, \text{m}) \), we will follow these steps:

### Step 1: Determine the Forces
We are given two forces:
- \( F_1 = 2\hat{i} + 3\hat{j} - \hat{k} \) N
- \( F_2 = \hat{i} - 2\hat{j} + 2\hat{k} \) N

### Step 2: Calculate the Resultant Force
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