force `F` on a partical moving in a straight line veries with distance `d` as shown in the figure. The work done on the partical during its displacement of `12 m` is

Explanation

Work done =Area under (force-displacement ) graph
`="Area of rectangle " ABCD + "Area of " DeltaDCE`
`="length" xx "breadth"+(1)/(2)xx"base height "`
`=(ABxxAD)+(1)/(2)xxDExxCD`

`=2xx(7-3)+(1)/(2)xx2xx(12-7)=8+(1)/(2)xx10=8+5=13 J`