A bullet weighing 10 g is fired with a velocity of `800 ms^(-1)`. After passing through a mud wall 1 m thick, its velocity decreases to `100 ms^(-1)`. Find the average resistance offered by the mud wall.

Explanation

According to work-energy theorem, work done by the average resistance offered by the wall =change in KE of the bullet.
`:.W=F.s=(1)/(2)mv^(2)-(1)/(2)"mu"^(2)`
`impliesF=(m(v^(2)-u^(2)))/(2s)=(0.01(100^(2)-800^(2)))/(2xx1)`
`implies=-3150 N`
`implies "Resistance offered" =3150 N`