Calculate the worked done in lifting a 300N weight to a height of 10m with an accelertaion `0.5ms^(2)`. Take g=`10ms^(-2)`.

Explanation

Given, Weight, w=300 N, Height, h=10 m
Acceleration, a=0.5 `ms^(-2)`
Here, `m=(w)/(g)=(300)/(10)`=30 kg, `F_(net)`=mg+ma
`:.` Work done, W=mgh+mah=m(a+g)h
=30(0.5+10)10=3150 J