When slow neutrons are incident on a target containing `underset(92)overset(235).U`, a possible fission reaction is
`underset(92)overset(235).U+underset(0)overset(1).nrarr underset(56)overset(141).Ba+underset(36)overset(92).Kr+3_(0)^(1)n`
Estimate the amount of energy released using the following data Given, mass of `underset(92)overset(235).U=235.04 amu`, mass of `underset(0)overset(1).n=1.0087 amu`, mass of `underset(56)overset(141).Ba=140.91 amu`, mass of `underset(36)overset(92).Kr=91.926 amu`, and energy equivalent to 1 amu=931 MeV.

Explanation

`underset(92)overset(235).U+underset(0)overset(1).ntounderset(56)overset(141).Ba+underset(36)overset(92).Kr+3underset(0)overset(1).n`
Total initial mass `(underset(92)overset(235).U+underset(0)overset(1).n)`=235.04+1.0087=236.0487 amu
Total final mass `(underset(56)overset(141).Ba+underset(36)overset(92).Kr+3underset(0)overset(1).n)=140.91+91926+3xx10087=235.8621 amu `
Decrease in mass,`Deltam=236.0487-235.8621=0.1866 amu`
Energy released =`Deltamxx931=0.1866xx931=173.725 MeV`