A force `F = Ay^(2)+By+C` acts on a body at rest in the `Y`-direction. The kinetic energy of the body during a displacement `y = -a` to `y = a` is

Options

A. `(2Aa^(3))/(3)`
B. `(2Aa^(3))/(3)+2Ca`
C. `(2Aa^(3))/(3)+(Ba^(2))/(2)+Ca`
D. None of these

Answer

B

Explanation

(b) `W=int_(-a)^(+a)Fdy=[(Ay^(3))/(3)+(By^(2))/(2)+Cy]_(-a)^(+a)=(2Aa^(3))/(3)+2Ca`