Two bodies of different masses `m_(1)` and `m_(2)` have equal momenta. Their kinetic energies `E_(1)` and `E_(2)` are in the ratio

Options

A. `sqrt(m_(2)/(m_(1)))`
B. `sqrt(m_(1)/(m_(2)))`
C. `(m_(1))/(m_(2))`
D. `(m_(2))/(m_(1))`

Answer

D

Explanation

(d)Kinetic energy `K=(p^(2))/(2m)`
` implies" "K_(1)=(p^(2))/(2m_(1)) " and " K_(2)=(p^(2))/(2m_(2))`
`:." "(K_(1))/(K_(2))=(m_(2))/(m_(1))`