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An engine develops 10 kW of power. How m...

An engine develops 10 kW of power. How much time will it take to lift a mass of 200 kg to a height of 40 m (`g=10(m)/(sec^2)`)`?

A

4 s

B

5 s

C

8 s

D

10 s

Text Solution

Verified by Experts

The correct Answer is:
C
(c ) `P=("Work done bt the engine")/("time taken")=(W)/(t)`
`:. T=(W)/(P)=(mgh)/(P)=(200xx10xx40)/(10xx10^(3))=8 s`
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