A rod of mass m and length l is lying on...

A rod of mass `m` and length `l` is lying on a horizontal table. Work done in making it stand on one end will be

mgl

`(mgl)/(2)`

`(mgl)/(4)`

2mgl

Text Solution

Verified by Experts

The correct Answer is:

(b) Centre of mass of the rod moves a height, `h=(1)/(2)`.
`W=mgh`=mgl//2`

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