Home
Class 11
PHYSICS
A mass of 5kg is moving along a circular...

A mass of `5kg` is moving along a circular path or radius `1m`. If the mass moves with 300 revolutions per minute, its kinetic energy would be

A

`250pi^(2)`

B

`100pi^(2)`

C

`5pi^(2)`

D

0

Text Solution

Verified by Experts

The correct Answer is:
A

(a) Given, mass =m=5 kg, `" "` Radius =1 m=R
Revolution per minute `omega =300 rev min^(-1)=10pi "rad" s^(-1)`
`rArr "linear speed" =v=omega R`
`=10pi ms^(-1)`
`KE=(1)/(2)mv^(2)=(1)/(2)xx5xx(10 pi)^(2)`
`=100pi^(2)xx5xx(1)/(2)=250 pi^(2) J`
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    DC PANDEY|Exercise MEDICAL ENTRANCE SPECIAL QUESTIONS|16 Videos
  • WORK, ENERGY AND POWER

    DC PANDEY|Exercise MATCH THE COLUMNS|7 Videos
  • WORK, ENERGY AND POWER

    DC PANDEY|Exercise CHECK POINT 6.3|10 Videos
  • WORK, ENERGY & POWER

    DC PANDEY|Exercise Level 2 Comprehension Based|2 Videos
  • WORK, POWER AND ENERGY

    DC PANDEY|Exercise E Integer Type Questions|11 Videos

Similar Questions

Explore conceptually related problems

A particle of mass m is moving along a circular path of radius r, with uniform speed v . The relation between its kinetic energy (E ) and momentum (P ) is given by

A cyclist moving in a circular path of radius 200 m covers half revolution in 5 minutes. Its average speed is

A cyclist moving on a circular track of radius 100 m completes one revolution in 4 minutes What is his average speed ?

If a particle of mass 1 gm is moving along a circular path of radius 1 m with a velocity of 1 m/s, then the its angular momentum is

A particle of mass 2 kg is moving along a circular path of radius 1 m. If its angular speed is 2pi" rad s"^(-1) , the centripetal force on it is

A particle of mass m is moving on a circular path of radius r with uniform speed v , rate of change of linear momentum is

An object of mass 50 kg is moving in a horizontal circle of radius 8 m . If the centripetal force is 40 N, then the kinetic energy of an object will be

A body of mass 1 kg is moving in a vertical circular path of radius 1 m. The difference between the kinetic energies at its highest and lowest position is

A body of mass 1 kg is moving in a vertical circular path of radius 1 m. The difference between the kinetic energies at its highest and lowest positions is [take g=10 m//s^2 ]

DC PANDEY-WORK, ENERGY AND POWER-EXERCISES(TAKING IT TOGETHER)
  1. Which of the diagrams shown in figure. Most closely shows the variatio...

    Text Solution

    |

  2. Which of the diagram shown in figures respresents variation of total m...

    Text Solution

    |

  3. A mass of 5kg is moving along a circular path or radius 1m. If the mas...

    Text Solution

    |

  4. A particle moves from position 3hati+2hatj-6hatk to 14hati+13hatj+9hat...

    Text Solution

    |

  5. A body moves from rest with a constant acceleration. Which one of the ...

    Text Solution

    |

  6. v-t graph of an object of mass 1 kg is shown.Select the wrong statemen...

    Text Solution

    |

  7. A toy gun a spring of force constant k. When changed before being trig...

    Text Solution

    |

  8. A car moving with a speed of 40 km//h can be stopped by applying the b...

    Text Solution

    |

  9. A long elastic spring is stretched by 2 cm and its potential energy is...

    Text Solution

    |

  10. A body intially at rest is falling under gravity. When it loses a grav...

    Text Solution

    |

  11. If a body of mass 200 g falls a height 200 m and its total P.E. is con...

    Text Solution

    |

  12. A stone of mass 2 kg is projected upwards with KE of 98 J. The height ...

    Text Solution

    |

  13. Mark out the correct statement(s).

    Text Solution

    |

  14. A vehicle needs an engine of 7500 W to keep it moving with a constant ...

    Text Solution

    |

  15. An engine exerts a force F=(20hati-3hatj+5hatk) N and moves with veloc...

    Text Solution

    |

  16. An object of mass m, initially at rest under the action of a constant ...

    Text Solution

    |

  17. A particle at rest on a frictionless table is acted upon by a horizont...

    Text Solution

    |

  18. The energy required to accelerate a car from 10 m/s to 20 m / s is how...

    Text Solution

    |

  19. A force F=-K(yhati+xhatj) (where K is a positive constant) acts on a p...

    Text Solution

    |

  20. Given that the displacement of the body in metre is a function of time...

    Text Solution

    |