A particle moves from position 3hati+2ha...

A particle moves from position `3hati+2hatj-6hatk` to `14hati+13hatj+9hatk` due to a force `vecF=(4hati+hatj+3hatk)`N. If the displacement is in centimeter then work done will be

1 J

2 J

3 J

2.5 J

Text Solution

Verified by Experts

The correct Answer is:

(a) `r_(1)=3hati+2hatj-6hatk, r_(2)=14hati+13hatj+9hatk`
`d=r_(2)-r_(1)=(11hati+11hatj+15hatk)cm`
`F=(4hati+hatj+3hatk) N`
`W=F.d=(44+11+45)xx10^(-2)=1 J`

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