A toy gun a spring of force constant `k`. When changed before being triggered in the upward direction, the spring is compressed by a distance `x`. If the mass of the shot is `m`, on the being triggered it will go up to a height of

Options

A. `(kx^(2))/(mg)`
B. `(x^(2))/(kmg)`
C. `(kx^(2))/(2mg)`
D. `((kx)^(2))/(mg)`

Answer

C

Explanation

(c ) Increase in gravitational potential energy
= decrease in elastic potential energy
`:. " " mgh=(1)/(2)kx^(2)`
`" " h=(kx^(2))/(2mg)`
`F_(brean)xxd=(1)/(2)mv^(2)`