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A body intially at rest is falling under...

A body intially at rest is falling under gravity. When it loses a gravitational potential energy by `U`, its speed is `V`.The mass of the body shall be `:`

A

`(2U)/(v)`

B

`(U)/(2v)`

C

`(2U)/(v^(2))`

D

`(U)/(2v^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

(c ) Applying conservation of mechanical energy we have,
`(1)/(2)mv^(2)=U" or "m=(2U)/(v^(2)`
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