Home
Class 11
PHYSICS
A stone of mass 2 kg is projected upward...

A stone of mass 2 kg is projected upwards with KE of 98 J. The height at which the KE of the body becomes half its original value, is given by (take, `g=9.8ms^(-2)`)

A

5 m

B

2.5 m

C

1.5 m

D

0.5 m

Text Solution

Verified by Experts

The correct Answer is:
B
(b) At this height, half is PE
`:. Mgh=(98)/(2)" or " 2xx9.8xxh=49" or " h=2.5 m`
Promotional Banner

Topper's Solved these Questions

  • WORK, ENERGY AND POWER

    DC PANDEY|Exercise MEDICAL ENTRANCE SPECIAL QUESTIONS|16 Videos

  • WORK, ENERGY AND POWER

    DC PANDEY|Exercise MATCH THE COLUMNS|7 Videos

  • WORK, ENERGY AND POWER

    DC PANDEY|Exercise CHECK POINT 6.3|10 Videos

  • WORK, ENERGY & POWER

    DC PANDEY|Exercise Level 2 Comprehension Based|2 Videos

  • WORK, POWER AND ENERGY

    DC PANDEY|Exercise E Integer Type Questions|11 Videos

Similar Questions

Explore conceptually related problems

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 2 kg is projected vertically upward with a velocity of 2msec^(-1) . The K.E. of the body just before striking the ground is

A ball is throuwn vertially up with a velcity of 20ms^(-1) . At height , will its K.E. be half its orginal value?

A body of mass 2 kg is thrown vertically upwards with K.E of 245 J. The acceleration due to gravity is 9.8 ms^(-2) . The K.E. Of the body will become half at the height of

A body of mass 2 kg is thrown up vertically with kinetic energy of 490 J . If g = 9.8m//s^(2) , the height at which the kinetic energy of the body becomes half of the original value, is

A stone of mass 0.4 kg is thrown vertically up with a speed of 9.8 ms^(-1) . Find the potential energy after half second.

DC PANDEY-WORK, ENERGY AND POWER-EXERCISES(TAKING IT TOGETHER)
  1. A body intially at rest is falling under gravity. When it loses a grav...

    Text Solution

    |

  2. If a body of mass 200 g falls a height 200 m and its total P.E. is con...

    Text Solution

    |

  3. A stone of mass 2 kg is projected upwards with KE of 98 J. The height ...

    Text Solution

    |

  4. Mark out the correct statement(s).

    Text Solution

    |

  5. A vehicle needs an engine of 7500 W to keep it moving with a constant ...

    Text Solution

    |

  6. An engine exerts a force F=(20hati-3hatj+5hatk) N and moves with veloc...

    Text Solution

    |

  7. An object of mass m, initially at rest under the action of a constant ...

    Text Solution

    |

  8. A particle at rest on a frictionless table is acted upon by a horizont...

    Text Solution

    |

  9. The energy required to accelerate a car from 10 m/s to 20 m / s is how...

    Text Solution

    |

  10. A force F=-K(yhati+xhatj) (where K is a positive constant) acts on a p...

    Text Solution

    |

  11. Given that the displacement of the body in metre is a function of time...

    Text Solution

    |

  12. A block is attached to a spring as shown and very-very gradually lower...

    Text Solution

    |

  13. A uniform chain of length L and mass M is lying on a smooth table and ...

    Text Solution

    |

  14. An object of mass m is tied to a string of length l and a variable for...

    Text Solution

    |

  15. A particle is moving in a conservative force field from point A to poi...

    Text Solution

    |

  16. Three particles A, B and C are thrown from the top of a tower with the...

    Text Solution

    |

  17. The force required to stretch a spring varies with the distance a show...

    Text Solution

    |

  18. Kinetic energy of a particle moving in a straight line varies with tim...

    Text Solution

    |

  19. A particle is released from height H. At cartain height from the groun...

    Text Solution

    |

  20. Power applied to a particle varices with time as P =(3t^(2)-2t + 1) wa...

    Text Solution

    |