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Three particles A, B and C are thrown fr...

Three particles A, B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speeds `v_(A), v_(B)` and `v_(C)` respectively:

A

`v_(A)=v_(B) gt v_(C)`

B

`v_(A)=v_(B)=v_(C)`

C

`v_(A) gt v_(B)=v_(C)`

D

`v_(B) gt v_(C) gt v_(A)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b)Change in potential energy for all three particles is same.
Hence, change in kinetic energy will also be same.
or `" " v_(A)=v_(B)=v_(C)`
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