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Power applied to a particle varices with...

Power applied to a particle varices with time as `P =(3t^(2)-2t + 1)` watt, where t is in second. Find the change in its kinetic energy between time `t=2s` and `t = 4 s` .

A

32 J

B

46 J

C

61 J

D

102 J

Text Solution

Verified by Experts

The correct Answer is:
B

(b) Change in kinetic energy of the particle
`DeltaKE=W=int_(2)^(4)Pdt=int_(2)^(4)(3t^(2)-2t+1)dt=[t^(3)-t^(2)+]_(2)^(4)=46J`
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