Power supplied to a mass `2 kg` varies with time as `P = (3t^(2))/(2)` watt. Here `t` is in second . If velocity of particle at `t = 0` is` V= 0`, the velocity of particle at time `t = 2s` will be:

Options

A. `1 ms^(-1)`
B. `4 ms^(-1)`
C. `2 ms^(-1)`
D. `2sqrt2 ms^(-1)`

Answer

C

Explanation

(c ) Work done,`W=int Pdt`
or `" " (1)/(2)mv^(2)=int Pdt=int_(0)^(2)((3t^(2))/(2))dt=8JrArr v=sqrt((8)/(2))=2ms^(-1)`