If `v` be the instantaneous velocity of the body dropped from the top of a power, when it is located at height `h`, then which of the following remains constant?

Options

A. `gh+v^(2)`
B. `gh+(v^(2))/(2)`
C. `gh-(v^(2))/(2)`
D. `gh-v^(2)`

Answer

B

Explanation

(b) `PE+KE=mgh+(1)/(2)mv^(2)`=constant
`=mgH " " (H="initial height" )`
or `gh+(v^(2))/(2)`=constant