A uniform chain has a mass M and length L. It is placed on a frictionless table with length `l_(0)` hanging over the edge. The chain begins to slide down. Ten, the speed v with which the end slides down from the edge is given by

Options

A. `v=sqrt((g)/(L)(L+l_(0)))`
B. `v=sqrt((g)/(L)(L-l_(0)))`
C. `v=sqrt((g)/(L)(L^(2)-l_(0)^(2)))`
D. `v=sqrt(2g`(L-l_(0)))`

Answer

C

Explanation

(c ) Decrease in gravitational PE=increase in kinetic energy

`(MgL)/(2)-(M)/(L).l_(0)"g"(l_(0))/(2)Mv^(2)`
or `" " v=sqrt((g)/(L)(L^(2)-L_(0)^(2)))`