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A block A of mass M rests on a wedge B o...

A block A of mass M rests on a wedge B of mass 2M and inclination `theta`. There is sufficient friction between A and B so that A does not slip on B. If there is no friction between B and ground, the compression in spring is

A

`(Mg costheta)/(k)`

B

`(Mg cos theta sin theta)/(k)`

C

`(Mg sin theta)/(k)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
(d) On M horizontal components of N and f are balanced (as Mg is vertical). Hence on 2M also they will be balanced.
`:.` Horizontal force Kx on 2M should be zero.
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