A body of mass `m`, accelerates uniformly from rest to `V_(1)` in time `t_(1)`. The instantaneous power delivered to the body as a function of time `t` is.

Options

A. `(mvit)/(t_(1))`
B. `(mv_(1)t)/(t_(1))`
C. `(mv_(1)t^(2))/(t_(1))`
D. `(mv_(1)^(2)t)/(t_(1)^(2))`

Answer

D

Explanation

(d) From `v=u+at, v_(i)=0+at_(i)`
`F=ma=(mv_(1))/(t_(1))" " (`:'a=(v_(1))/(t_(1))`)`
Velocity acquired in t second `=at rArr v=(v_(1))/(t_(1))t`
`"Power"=Fv=((mv_(1))/(t_(1)))((v_(1))/(t_(1))t)=((mv_(1)^(2))/(t_(1)^(2)))t`