Under the action of a force F = Cx, the position of a body changes from 0 to x. The work done is

Options

A. `(1)/(2)Cx^(2)`
B. `Cx^(2)`
C. Cx
D. `(1)/(2)C x`

Answer

A

Explanation

(a) Work done, `W=int_(0)^(x)F.dx=int_(0)^(x)"C x dx"=C((x^(2))/(2))_(0)^(x)=(1)/(2)Cx^(2)`.