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A 5 m long aluminium wire (Y=7xx10^10(N)...

A 5 m long aluminium wire `(Y=7xx10^10(N)/(m^2))` of diameter 3 mm supprts a 40 kg mass. In order to have the same elongation in a copper wire `(Y=12xx10^10(N)/(m^2))` of the same length under the same weight, the diameter should now, in mm

A

1.75

B

1.65

C

2.5

D

`5.0`

Text Solution

Verified by Experts

The correct Answer is:
C
(c) For twisting, angle of shear `phi prop (1)/(L)`
i.e., if L is more , then `phi` will be small.
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