A cable that can support a load W is cut into two equal parts .T he maximum load that can be supported by either part is

Options

A. `(W)/(4)`
B. `(W)/(2)`
C. W
D. 2W

Explanation

To solve the problem, we need to analyze the situation of the cable being cut into two equal parts and how that affects the maximum load that each part can support.

### Step-by-Step Solution:

1. **Understanding the Initial Condition:**
- The original cable can support a maximum load \( W \).
- Let the cross-sectional area of the cable be \( A \).
- The stress in the cable when it supports the load \( W \) is given by the formula:
\[ \text{Stress} = \frac{\text{Load}}{\text{Area}} = \frac{W}{A} \]

2. **Cutting the Cable:**
- When the cable is cut into two equal parts, each part still has the same cross-sectional area \( A \).
- The length of each part is now half of the original length, but the cross-sectional area remains unchanged.

3. **Analyzing Each Part:**
- Let \( T \) be the maximum load that can be supported by either part after the cable is cut.
- The stress in each part when it supports the load \( T \) is:
\[ \text{Stress} = \frac{T}{A} \]

4. **Equating the Stress:**
- Since the material properties of the cable do not change when it is cut, the maximum stress that can be supported remains the same. Therefore, we can set the stresses equal:
\[ \frac{W}{A} = \frac{T}{A} \]

5. **Cancelling the Area:**
- Since the cross-sectional area \( A \) is the same for both parts, we can cancel \( A \) from both sides of the equation:
\[ W = T \]

6. **Conclusion:**
- Thus, the maximum load \( T \) that can be supported by either part after cutting the cable is equal to the original maximum load \( W \).
- Therefore, the answer is:
\[ T = W \]

### Final Answer:
The maximum load that can be supported by either part after cutting the cable is \( W \).

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