A stress of `10^(6) N//m^(2)` is required for breaking a material. If the density of the material is `3 xx 10^(3) Kg//m^(3)`, then what should be the minimum length of the wire made of the same material so that it breaks by its own weight `(g = 10m//s^(2))`

Options

A. 10 m
B. 33.3 m
C. 5 m
D. 66.6 m

Answer

B

Explanation

(b) Maximum breaking stress `=(F)/(A)=(mg)/(A)` or `((Alrho)g)/(A)=sigma_("max")`
`therefore l_("max")=(sigma_("max"))/(rhog)=(10^(6))/((3xx10^(3))(10))=33.33 m`