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A uniform steel rod of cross- sectional ...

A uniform steel rod of cross- sectional area `A` and `L` is suspended so that it hangs vertically. The stress at the middle point of the rod is

A

`(L)/(2A)rhog`

B

`(Lrhog)/(2)`

C

`(LA)/(rhog)`

D

`Lrhog`

Text Solution

Verified by Experts

The correct Answer is:
B
(c) At middle , T=weight of half the length of steel bar
`=((L)/(2))Arhog`
`therefore` Stress `=(T)/(A)=(Lrhog)/(2)`
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