The density of a metal at normal pressure is `rho`. Its density when it is subjected to an excess pressure p is `rho'` . If B is the bluk modulus of the metal, then find the ratio `rho'//rho`.

Options

A. `(1)/(1-(p)/(B))`
B. `1+(B)/(P)`
C. `(1)/(1-(B)/(P))`
D. `1+(p)/(B)`

Answer

A

Explanation

(a) Density , `rho=(m)/(V)` or `rho=(1)/(V)" "` (as m=constant)
`therefore (rho')/(rho)=(V)/(V')=(V)/(V+dV)" "`(as `B=-(p)/(dV//V)`)
`therefore (rho')/(rho)=(V)/(V-(Vp)/(B))=(1)/(1=(p)/(B))`