Find the pressure exerted below a column of water, open to the atmosphere, at depth (i) 10 m " " (ii) 30 m (Given, density of water `=1xx10^(3)kgm^(-3), g =10 ms^(-2))`
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To find the pressure exerted below a column of water at a given depth, we can use the hydrostatic pressure formula:
\[ P = P_0 + \rho g h \]
Where:
- \( P \) is the total pressure at depth,
- \( P_0 \) is the atmospheric pressure (approximately \( 1.013 \times 10^5 \, \text{Pa} \)),
- \( \rho \) is the density of the fluid (for water, \( \rho = 1 \times 10^3 \, \text{kg/m}^3 \)),
...
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