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Find the pressure exerted below a column...

Find the pressure exerted below a column of water, open to the atmosphere, at depth
(i) 10 m " " (ii) 30 m
(Given, density of water `=1xx10^(3)kgm^(-3), g =10 ms^(-2))`

Text Solution

AI Generated Solution

To find the pressure exerted below a column of water at a given depth, we can use the hydrostatic pressure formula: \[ P = P_0 + \rho g h \] Where: - \( P \) is the total pressure at depth, - \( P_0 \) is the atmospheric pressure (approximately \( 1.013 \times 10^5 \, \text{Pa} \)), - \( \rho \) is the density of the fluid (for water, \( \rho = 1 \times 10^3 \, \text{kg/m}^3 \)), ...
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Knowledge Check

  • The guage pressure exerted below a column of water, open to the earth's atmosphere at depth of 10 m is (density of water = 1000 kg/ m^3 , g = 10 m/ s^2 and 1 atm pressure = 10^5 Pa)

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    A
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    C
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    D
    10 cm

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    A
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    D
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