Density of ice is `900 kg//m^(3)`. A piece of ice is floating in water of density `1000kg//m^(3)`. Find the fraction of volume of the picec of ice outside the water.
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Let V be the total volume and `V_(1)` the volume of ice piece immersed in water. For equilibrium of ice piece, weight =upthrust `therefore " " V rhoig=V_(i) rho_(w)g` Here, `rho_(i)`=density of water`=900 kgm^(-3)` and `rho_(w)`=density of water `=1000kgm^(-3)` Substituting in Eq. (i), we get `(V_(i))/(V)=(rho_(i))/(rho_(w))=(900)/(1000)=0.9` i.e., the fraction of volume outside the water, f=1-0.9=0.1
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