A liquid is kept in a beaker of radius 4 cm. Consider a diameter of the beaker on the surface of the water. Find the force by which the surface on one side of the diameter pulls the surface on the other side. Surface tension of liquid `=0.075 Nm^(-1)`
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The length of the diameter is l=2r=8 cm =0.08 m The surface tension is `S=F//l`. Thus, `F=Sl=(0.075 Nm^(-1))xx(0.08 m)=6xx10^(-3)N`
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