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Two equal drops of water are falling thr...

Two equal drops of water are falling through air with a steady velocity v. If the drops coalesced, what will be the new velocity?

A

2v

B

`sqrt(2)v`

C

`2^(2//3)v`

D

`(v)/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
Let r be the radius of smaller drop and R the radius of bigger drop. By equating the volume we have,
`2((4)/(3)pi r^(3))=(4)/(3)pi R^(3) " or" R=(2)^(1//3)`.r
Now terminal velocity `prop ("radius")^(2)`
`therefore " " v'=(2)^(2//3)v`
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