A piston of cross-sectional area `100 cm^(2)` is used in a hydraulic pressure to exert a force of `10^(7)` dyne on the water. The cross-sectional area of the other piston which support a truck of mass 2000 kg is

Options

A. `9.8xx10^(2) cm^(2)`
B. `9.8xx10^(3) cm^(2)`
C. `1.96xx10^(3) cm^(2)`
D. `1.96xx10^(4) cm^(2)`

Answer

D

Explanation

`F_(1)/A_(1)=F_(2)/A_(2)" "("Pascal's law")`
`therefore" "A_(2)=F_(2)/F_(1).A_(1)=((2000xx9.8)/(10^(2)))(100)=1.96xx10^(4)cm^(2)`