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The level of water in a tank is 5 m high...

The level of water in a tank is 5 m high. A hole of area of cross section 1 `cm^(2)` is made at the bottom of the tank. The rate of leakage of water for the hole in `m^(3)s^(-1)` is `(g=10ms^(-2))`

A

`10^(-3) m^(3)s^(-1)`

B

`10^(-4) m^(3)s^(-1)`

C

`10 m^(3)s^(-1)`

D

`10^(-2) m^(3)s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

Rate of leakage of water of from the hole
`=Av=Asqrt(2gh)=10^(-4)sqrt(2xx10xx5)=10^(-3)m^(3)s^(-1)`
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