Water is flowing through two horizontal pipes of different diameters which are connected together. The diameters of the two pipes are 3 cm and 6 cm respectively. If the speed of water in the narrower tube is `4 ms^(-1)`. Then the speed of water in the wider tube is

Options

A. `16 ms^(-1)`
B. `1 m s^(-1)`
C. `4 m s^(-1)`
D. `2 m s^(-1)`

Answer

B

Explanation

From continutiy equation `v prop 1/A" or v "prop1/d^(2)`
(d = diameter of pipe)
`v_("narrow")/v_("Wider")d_(w)/d_(N)=(6/3)=rrArrv_("Wider")=v_("narrow")/4=4/4=1 ms^(-1)`