A cubical vessel of height `1` m is full of water. What is the workdone in pumping water out of the vessel?

Options

A. 1250 J
B. 5000 J
C. 1000 J
D. 2500 J

Answer

B

Explanation

The volume of water contained in the vessel would be equal to `V=I^(3)=(1m)^(3)`. Assuming water to be pure so the density of water would be equal to `d = 1000 kgm^(-3)`, hence the mass of water containded in the vessel would be equal to m = Vd = 1000 kg.
Thus, the work done would be equal to
`W=mgh=1000xx10xx1/2=5000 j`