Two substances of densities `rho_(1)` and `rho_(2)` are mixed in equal volume and the relative density of mixture is `4`. When they are mixed in equal masses, the relative density of the mixture is 3. the values of `rho_(1)` and `rho_(2)` are:

Options

A. `rho=6 " and " rho_(2)=2`
B. `rho_(3) " and " rho_(2)=5`
C. `rho_(1)=12 " and " rho_(2)=4`
D. None of these

Answer

A

Explanation

Density of the mixture
`4=(rho_(1)V+rho_(2)V)/(2V) " or" rho_(1)+rho_(2)=8`
`3=(m+m)/((m//rho_(1))+(m//rho_(2))) " or " (rho_(1)rho_(2))/(rho_(1)+rho_(2))=(3)/(2)`
Solving these two equations, we get `rho_(1)=6 " and " rho_(2)=2`