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A capillary tube is dipped in a liquid. ...

A capillary tube is dipped in a liquid. Let pressure at point `A,B` and `C` be `p_(A)p_(B)` and `p_(C)` respectively, then

A

`p_(A)=p_(B)=p_(C )`

B

`p_(A)=p_(B) lt p_(C )`

C

`p_(A) =P_(C ) lt p_(B)`

D

`p_(A) = p_(C ) gt p_(B)`

Text Solution

Verified by Experts

The correct Answer is:
D
`p_(A)=p_(C )=p_(0) " and" p_(B)=p_(0)-(2T)/(R )`
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