A solid floats such that its `1//3` part is above the water surface. Then, the density of solid is

Options

A. `744 kgm^(-3)`
B. `(1000)/(3)kgm^(-3)`
C. `(2000)/(3) kgm^(-3)`
D. `910 kgm^(-3)`

Answer

C

Explanation

Volume of part above the water surface `=V/3` `(therefore V`=volume of solid)
Volume of solid inside the water surface `=V-V/3=(2V)/(3)`
Weight of displaced water
`W=(2V)/(3) xx 10^(3) xx g`
Now, weight of the body= Weight of displaced water
`rArr rho=2/3 xx 1000 = 2000/3 kg m^(-3)`