An astronomical telescope has an angular magnification of magnitude 5 for distant object. The separation between the objective and the eyepiece is 36 cm and the final image is formed at infinity. The focal length `f_(0)` of the objective and the focal length `f_(0)` of the eyepiece are

Answer

D

Explanation

(d) In this case, `abs(m)=f_(0)/(f_(e))=5`
and the length of telescope = `f_(0)+f_(e)=36`
On solving Eqs. (i) and (ii), we get
`f_(e)=6 cm, f_(0)=30 cm`