Wavelength of given light waves in air and in a medium are 6000 Å and 3000 Å, respectively. The critical angle is

Options

A. `tan^(-1)(2/3)`
B. `tan^(-1)(3/2)`
C. `sin^(-1)(2)`
D. `sin^(-1)(3/2)`

Answer

C

Explanation

(c ) We have, `1/SinC=lamda_(1)/lamda_(2)`
`rArr 1/sinC=6000/3000`
`rArr1/sinC=6/3=2`
`rArrsinC=1/2`
`rArr` Criticle angle between two medium, `C=sin^(-1)(1/2)`