If light travels a distance `x` in `t_(1)` sec in air and `10x` distance in `t_(2)` sec in a medium, the critical angle of the medium will be

Options

A. 24 cm
B. 10 cm
C. 15 cm
D. 120 cm

Answer

C

Explanation

(c ) From the formula, sin C`=1/(""_(1)mu_(2))`
`rArrsinC=""_(2)mu_(2)`
`mu_(1)/mu_(2)=v_(2)/v_(1)`
`rArrsin C=(10x//t_(1))/(x//t_(1))`
`sinC=(10t_(1))/t_(2)`
`C=sin^(-1)((10t_(1))/t_(2))`