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what is the nuclear radius of .^(125)...

what is the nuclear radius ` of .^(125)` Fe , if that of `"".^(27) Al `is 6.4 fermi?

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Radius of the nucleus is ,
`R=R_(0)A^(1//3)`
`(R_(Fe))/(R_(Al))=((A_(Fe))/(A_(Al)))^(1//3)=((125)/(27))^(1//3)`
`Radius ,R_(Fe) =(5)/(3) R_(Al)=(5)/(3)xx6.4=10Fm`
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