Assuming that protons and neutrons have equal masses, calculate how many times nuclear matter is denser than water. Take mass of a nucleon `=1.67xx10^(-27)kg and R_(0)=1.2xx10^(-15)m`.

Explanation

density of nucleus (of water )
`rho =(3m) /(4piR_(0)^(3))=(1xx1.67xx10^(-27))/(4xx(22)/(7)xx(1.2xx10^(-15))^(3))`
`=(7xx3xx1.67xx10^(18))/(88xx1.2xx1.2xx1.2)=2.307xx10^(17)kg //m^(3)`
Density of water ` rho ' =10^(3) kg //m^(3)`
`therefore (rho)/(rho ')=(2.307xx10^(17))/(10^(3))=2.307xx10^(14)`