Find the amount of energy released when `1` atom of Uranium `._(92)U^(235)(235.0439 "amu")` undergoes fission by slow neturon `(1.0087 "amu")` and is splitted into Krypton `._(36)Kr^(92)(91.8973 "amu")` and Barium `._(56)Br^(141)(140.9139 "amu")` assuming no energy is lost. Hence find the enrgy in `kWh`, when `1g` of it undergoes fission.

Explanation

fission equation , `""_(92)U^(235)+ ""_(0)n^(235) to ""_(56)Ba^(141) +""_(36)Kr^(92)+3(""_(0)n^(1))`
Mass defect
`Delta m= [m(""_(92)U^(235))+m_(n)]-[m(""_(66)Ba^(141))+m(""_(36)Kr^(92))+ 3m_(n)]`
`={[235.0439+1.0087}-{140.9139+91.8973+3xx1.0087}]`
=0.2135 amu
Equivalent energy ,`E=Delta mc^(2)=Delta mxx931Me V `
`=0.2153xx931=200 MeV `
number of atoms / Fussion of 1g of atom is
`n=(N_(A))/(A) =(1)/(235)xx6.023xx10^(23) =2.56xx10^(21)`
Energy reeased in fission of 1 g of `""_(92)^(235) U `
`implies nxxe=2.56xx10^(21)xx200Me V `
`-2.56xx10^(21)xx200 xx1.6xx10^(-13)J`
` (:' MeV = 1.6xx10^(-13)J)`
`=(2.56xx10^(21)xx200xx1.6xx10^(-13))/(2.6xx10^(6))KWh`
`=2.28xx10^(4)`KWh