The binding energy per nucleon of deuterium and helium atom is `1.1 MeV` and `7.0 MeV`. If two deuterium nuclei fuse to form helium atom, the energy released is.

Explanation

Given fusion reaction , `""_(1)H^(2)+""_(1)H^(2)to ""_(2)He^(4)+`energy
Bindng energy of a`(""_(1)H^(2))` deuterium nuclei
`=2xx1.1=2.2MeV`
Total binding energy of two deuterium nuclei
`=2.2xx2= 4.4Me V `
Binding energy of a `(""_(2)He^(4))` nuclei `=4xx7=28` Me V
So , energy released in fusion -final BE -initialBE
`=28-44=23.6Me V `